Curl: definition, physical meaning, computation

At a Glance

Why This Chapter Matters

All four appearances of this atom are classified easy — this is guaranteed-mark territory. Every question follows an identical two-step pattern: set each component of ×F\nabla \times \vec F to zero to find unknown parameters, then integrate to recover the scalar potential. The 2017 question adds the minor twist of expressing the divergence in cylindrical coordinates (but since divergence is a scalar invariant, the value is just the Cartesian answer). Investing 15 minutes to internalize the curl formula and the potential-recovery algorithm pays off on four separate years.

Minimum Theory

Curl. For F=Pi^+Qj^+Rk^\vec F = P\hat i + Q\hat j + R\hat k: ×F=(RyQz)i^(RxPz)j^+(QxPy)k^.\nabla \times \vec F = (R_y - Q_z)\hat i - (R_x - P_z)\hat j + (Q_x - P_y)\hat k. Remembered as the 3×33\times3 determinant with rows (i^,j^,k^)(\hat i, \hat j, \hat k), (x,y,z)(\partial_x, \partial_y, \partial_z), (P,Q,R)(P, Q, R).

Irrotational field. ×F=0\nabla \times \vec F = \vec 0 (all three components vanish). This is the necessary and sufficient condition (on a simply connected domain) for the existence of a scalar potential ϕ\phi with F=ϕ\vec F = \nabla\phi.

Potential recovery. Given ϕ=F=(P,Q,R)\nabla\phi = \vec F = (P,Q,R):

  1. Integrate ϕx=P\phi_x = P with respect to xxϕ=Pdx+g(y,z)\phi = \int P\,dx + g(y,z).
  2. Differentiate w.r.t. yy and match QQ → determine gyg_y, integrate → g=()dy+h(z)g = \int(\cdots)\,dy + h(z).
  3. Differentiate w.r.t. zz and match RR → determine h(z)h'(z), integrate.

Curl formula (left) and circulation-density interpretation (right): \nabla\times\vec F = \vec 0 (irrotational) implies \vec F = \nabla\phi (conservative).

Question Archetypes

ArchetypeRecognition cue
irrotational-potential”Verify F\vec F is irrotational; find scalar potential ϕ\phi.“
find-params-irrotational”For what values of a,b,ca,b,c is V\vec V irrotational?“

irrotational-potential (2 questions; 2015, 2022)

Recognition Cues

Solution Template

  1. Compute curl components. Three partial-derivative differences: (RyQz)(R_y-Q_z), (PzRx)(P_z-R_x), (QxPy)(Q_x-P_y). Show each is 0.
  2. Integrate ϕx=P\phi_x = P w.r.t. xx: ϕ=Pdx+g(y,z)\phi = \int P\,dx + g(y,z).
  3. Match ϕy=Q\phi_y = Q: differentiate the result w.r.t. yy; solve for gyg_y; integrate to get gg.
  4. Match ϕz=R\phi_z = R: differentiate w.r.t. zz; solve for h(z)h'(z); integrate.
  5. State ϕ\phi with arbitrary constant CC.

Worked Example(s)

2022 Paper 1, 2022-P1-Q5e (10 marks)

Show A=(6xy+z3)i^+(3x2z)j^+(3xz2y)k^\vec A = (6xy+z^3)\hat i + (3x^2-z)\hat j + (3xz^2-y)\hat k is irrotational; find ϕ\phi.

Curl:

Potential:

ϕ=3x2y+xz3yz+C.\boxed{\phi = 3x^2y + xz^3 - yz + C.}


2015 Paper 1, 2015-P1-Q7c (12 marks)

Verify F=(x2+xy2)i^+(y2+x2y)j^\vec F = (x^2+xy^2)\hat i + (y^2+x^2y)\hat j is irrotational; find scalar potential.

2D field (no zz-component, no zz-dependence): only the k^\hat k curl component matters.

k^\hat k: x(y2+x2y)y(x2+xy2)=2xy2xy=0\partial_x(y^2+x^2y) - \partial_y(x^2+xy^2) = 2xy - 2xy = 0 ✓. Irrotational.

Potential:

ϕ=x33+x2y22+y33+C.\boxed{\phi = \frac{x^3}{3} + \frac{x^2y^2}{2} + \frac{y^3}{3} + C.}

Common Traps


find-params-irrotational (2 questions; 2017, 2020)

Recognition Cues

Solution Template

  1. Write the three curl components as functions of a,b,ca,b,c.
  2. Set each to zero to get 3 equations.
  3. Solve (usually one equation per parameter).
  4. State the potential by integrating the field with the found parameters.

Worked Example(s)

2020 Paper 1, 2020-P1-Q5c (10 marks)

Find a,b,ca,b,c for V=(4x3y+az)i^+(bx+3y+5z)j^+(4x+cy+3z)k^\vec V = (-4x-3y+az)\hat i + (bx+3y+5z)\hat j + (4x+cy+3z)\hat k to be irrotational.

Curl components:

a=4,  b=3,  c=5.\boxed{a=4,\; b=-3,\; c=5.}

Potential: with these values, integrate as in the template: ϕ=2x2+32y2+32z23xy+4xz+5yz+C.\phi = -2x^2 + \tfrac{3}{2}y^2 + \tfrac{3}{2}z^2 - 3xy + 4xz + 5yz + C.


2017 Paper 1, 2017-P1-Q5d (10 marks)

Find a,b,ca,b,c for V=(x+y+az)i^+(bx+2yz)j^+(x+cy+2z)k^\vec V = (x+y+az)\hat i + (bx+2y-z)\hat j + (-x+cy+2z)\hat k to be irrotational; find the divergence in cylindrical coordinates.

Curl:

a=1,  b=1,  c=1.\boxed{a=-1,\; b=1,\; c=-1.}

Divergence in cylindrical coordinates. The divergence V\nabla \cdot \vec V is a scalar invariant — its value is independent of the coordinate system. In Cartesian: V=x(x+yz)+y(x+2yz)+z(xy+2z)=1+2+2=5.\nabla \cdot \vec V = \partial_x(x+y-z) + \partial_y(x+2y-z) + \partial_z(-x-y+2z) = 1+2+2 = 5. In cylindrical coordinates, the divergence formula gives the same constant 55.

Common Traps

Marks-Aware Writing

10-mark irrotational + potential: Show three curl components vanish (3 lines). Then three integration steps for the potential (3 lines). State the answer. Total ~7 lines.

10-mark find-params + divergence: Three one-line equations from curl = 0 (immediate). State the divergence (one line) and note coordinate invariance (one sentence).

Practice Set

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This chapter is part of the Maths Coverage Map — 13 years, mapped. Get the take-away PDF free.