CSAT Solved Papers/ 2021/Q56

2021 CSAT — Q56

Quant Logical & quantitative reasoning 2.5 marks Medium

In a code language ‘MATHEMATICS’ is written as ‘LBSIDNZUHDR’. How is ‘CHEMISTRY’ written in that code language?

  1. A DIDLHRSSX
  2. B BIDNHTSSX Answer
  3. C BIDLHTSSX
  4. D DGFLIRUQZ

Worked rationale

Compare each letter of MATHEMATICS to its code, using alphabet positions (A=1,…,Z=26A=1,\dots,Z=26), and read the shift per position:

pos1234567891011
plainMATHEMATICS
codeLBSIDNZUHDR
shift−1-1+1+1−1-1+1+1−1-1+1+1−1-1+1+1−1-1+1+1−1-1

The rule is −1-1 on odd positions, +1+1 on even positions (with wrap-around, e.g. position 77: A→ZA\to Z). Apply it to CHEMISTRY (99 letters):

pos123456789
plainCHEMISTRY
shift−1-1+1+1−1-1+1+1−1-1+1+1−1-1+1+1−1-1
codeBIDNHTSSX

So CHEMISTRY →\to BIDNHTSSX.

Answer: (b) BIDNHTSSX.

Why the other options miss

  • A
    the parity flipped backwards: flips the parity (uses +1+1 on odds, −1-1 on evens) at the start, giving C→DC\to D, M→LM\to L.
  • C
    an arithmetic slip: correct rule but slips on position 44 (M→LM\to L instead of NN), one letter off.
  • D
    the wrong rule applied: applies a uniform shift (all +1+1 or a Caesar-style constant) instead of the alternating ∓1\mp 1.

Specialist insight

The decode is not a single Caesar shift — the shift alternates with position parity (−1,+1,−1,+1,…-1,+1,-1,+1,\dots). Recover it by tabulating plain-vs-code differences before touching the target word; the clean ∓1\mp1 pattern (and the A→ZA\to Z wrap at an odd slot) confirms the rule. Then it’s mechanical, but watch the even slots (+1+1: H→IH\to I, M→NM\to N, S→TS\to T, R→SR\to S) where the off-by-one distractor (c) is planted.

The trap, in one line

Shift is −1-1 on odd positions, +1+1 on even; CHEMISTRY →\to BIDNHTSSX ⇒\Rightarrow (b).

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